The diagram shows stream gradient. if a stream has a horizontal distance of 10 km and begins at an elecation 100m higher than where it ends, what is its stream gradient
a) 100m x 10km = 1000m/km
b) 100m / 10km = 10m/km
c) 10km + 100m = 110km/m
d) 10km / 100m = 0.10km/m

it's filtration, but this is an assumption so my apologies if i got this

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole