You react 105g of lithium nitride and excess water, and you get 48g of lithium hydroxide. what is the percent yield?

Percent yield = 22.26%

Explanation:

Given data:

Mass of lithium nitride = 105 g

Mass of lithium hydroxide produces = 48 g

Percent yield = ?

Solution:

Chemical equation:

Li₃N   +   3H₂O  →  3LiOH + NH₃

Number of moles of lithium nitride :

Number of moles = mass/ molar mass

Number of moles = 105 g/ 34.83 g/mol

Number of moles = 3 mol

Now we will compare the moles of lithium nitride with lithium hydroxide.

                   Li₃N         :          LiOH

                      1            :              3

                      3            :            3×3 = 9 mol

Mass of lithium hydroxide:

Mass = number of moles × molar mass

Mass = 9 mol × 23.95 g/mol

Mass = 215.6 g

Percent yield:

Percent yield = actual yield / theoretical yield × 100

Percent yield =   48 g/ 215.6 g × 100

Percent yield = 22.26%

the answer is 303.15 or 303