Which conversion factor do you use first to calculate the number of grams of co 2 produced by the reaction of 50.6 g of ch 4 with o 2?

Thus, first conversion of mass of methane into moles by dividing it with 16.04 g/mol

Mass =  138.63 g

Explanation:

The balanced chemical reaction is shown below:-

Firstly the moles of methane gas reacted must be calculate as:-

Given, mass of methane = 50.6 g

Molar mass of methane gas = 16.04 g/mol

The formula for the calculation of moles is:-

Thus, from the reaction stoichiometry,

1 mole of methane produces 1 mole of carbon dioxide

Also,

3.15 mole of methane produces 3.15 mole of carbon dioxide

Moles of = 3.15 mole

Molar mass of = 44.01 g/mol

Mass = Moles*Molar mass = g = 138.63 g

false

because it does not have the potential to be entirely used up

i believe the answer is a.