Electron in the n = 4 state with ml = 2, what are the possible values of l?

l= 2, 3

Explanation:

Given the principal quantum number, n, we have that the angular momentum number from 0 to n-1, and the magnetic quantum number can have the values from - l to + l.

For n= 4 ( principal quantum number ) , we have that l, angular quantum number,  can  have the values 0, 1, 2, 3, and for each l value ml, magnetic quantum number, can have the values from - l  to + l :

ml ( for l=0 ) : 1   (s orbital)

ml ( for l= 1 ) : -1, 0, +1 ( p orbitals )

ml ( for l= 2 ) : -2,-1,0,+1,+2 ( d orbitals )

ml ( for l= 3 ) : -3,-2,-1,0+,1,+2 (f orbitals )

So we see that the possible values of l for ml = 2 are l= 2 and l=3

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be