Acompression at a constant pressure of 200 kpa is performed on 8.00 moles of an ideal monatomic gas. the compression reduces the volume of the gas from 0.200 m3 to 0.120 m3. how much work was done by the gas during this process?

workdone = 16kJ

Explanation:

Workdone  for an Isobaric process = PΔV (1)

                                  = P (V₁-V₂)(2)

P = 200kPa ; 200,000 N/m²

V₁ = 0.200 m³

V₂ =  0.120 m³

Substituting into (2) we have:

Workdone =  200,000 (0.200-0.120)

                  =   200,000 (0.080)

                  =16,000Nm

                  = 16,000Joules

                  = 16kJ