Ineed to make this into an ionic equation with state symbols

Pb²⁺(aq) +  2I⁻(aq) ⟶ PbI₂(s)  

Explanation:

There are three steps you must follow. You must write the:

A. Molecular equation

Pb(NO₃)₂(aq) + 2KI(aq) ⟶ PbI₂(s) + 2KNO₃(aq)

B. Ionic equation

You write all the soluble substances as ions.

Pb²⁺(aq)+ 2NO₃⁻(aq) + 2K⁺(aq) + 2I⁻(aq) ⟶ PbI₂(s) + 2K⁺(aq) + 2NO₃⁻(aq)

C. Net ionic equation

To get the net ionic equation, you cancel the ions that appear on each side of the ionic equation.

Pb²⁺(aq) + 2NO₃⁻(aq) + 2K⁺(aq) + 2I⁻(aq) ⟶ PbI₂(s) + 2K⁺(aq) + 2NO₃⁻(aq)

The net ionic equation is

Pb²⁺(aq) +  2I⁻(aq) ⟶ PbI₂(s)  

you need to have a picture of the atom that way we can answer it