Amixture of 02 and n2 at a total pressure of 1.6 atm is found to contain 3 mol of o2 and 7 mol of n2. the partial pressure of o2 is atm.

0.48atm

Explanation:

Firstly, we need to know the mole ratio of the oxygen gas involved. To do this, we simply place the number of moles of the oxygen over the sum of both gases.

This would be 3/(3+7) = 0.3

Now, to get the partial pressure contributed by the oxygen gas, we simply multiply the 0.3 by the total pressure

Hence, the partial pressure of oxygen = the mole fraction of oxygen * the total pressure.

= 0.3 * 1.6 = 0.48atm

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