Show the calculation of the mass of ca3(po4)2 needed to make 200 ml of a 0.128 m solution.

We need 7.94 grams of Ca3(PO4)2

Explanation:

Step 1: Data given

Volume of Ca3(PO4)2 = 200 mL = 0.2 L

Molarity = 0.128 M

Molar mass of Ca3(PO4)2 = 310.18 g/mol

Step 2: Calculate moles of Ca3(PO4)2

Moles = molarity * volume

Moles Ca3(PO4)2  = 0.128 M * 0.2 L

Moles Ca3(PO4)2  = 0.0256 moles

Step 3: Calculate mass of Ca3(PO4)2

Mass Ca3(PO4)2  = moles Ca3(PO4)2  * molar massCa3(PO4)2

Mass Ca3(PO4)2  = 0.0256 moles * 310.18 g/mol

Mass Ca3(PO4)2  = 7.94 grams

We need 7.94 grams of Ca3(PO4)2

the answer is learned

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