A35.00ml sample of naoh solution is titrated to an endpointby
14.76 ml 0.4122m hbr solution. what is the molarity of themolarity
of the naoh solution.

0.1738 M

Explanation:

Let's consider the neutralization reaction between NaOH and HBr.

NaOH + HBr → NaBr + H₂O

The moles of HBr are:

14.76 × 10⁻³ L × 0.4122 mol/L = 6.084 × 10⁻³ mol

The molar ratio of NaOH to HBr is 1:1. In the endpoint, they have reacted completely, so the moles of NaOH were 6.084 × 10⁻³ mol before the reaction.

The molarity of NaOH is:

M = 6.084 × 10⁻³ mol / 35.00 × 10⁻³ L = 0.1738 M

l dont know l am s sorry