Find the ph of a 0.00580 m solution of the strong
basekoh.

11.76

Explanation:

Potassium hydroxide is a strong base that dissociates completely according to the following reaction.

KOH(aq) → K⁺ + OH⁻

Then, the concentration of OH⁻ will be 0.00580 M.

The pOH of the solution is:

pOH = -log [OH⁻]

pOH = -log 0.00580 = 2.24

We can calculate the pH using the following expression.

pH + pOH = 14

pH = 14 - pOH = 14 - 2.24 = 11.76

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