How many moles of ammonium nitrate (nh4no3) are required to decompose to produce 0.90 moles of water (h2o)?

The answer to your question is 0.45 moles

Explanation:

Balanced equation

                               NH₄NO₃   ⇒   N₂O  +  2H₂O

                                2 -----------  N ----------- 2

                                4 ------------ H ----------- 4

                                3 ------------ O ----------- 3

From the balanced equation we know that 1 mol of NH₄NO₃ produces 2 moles of water, so we use proportions to find the amount of NH₄NO₃ required  to produce 0.9 moles of water.

                               1 mol of NH₄NO₃ -------------  2 moles of water

                               ?                           -------------- 0.9 moles of water

Use cross multiplication

                               x =

Simplification

                               x = 0.9 / 2

Result

                               x = 0.45 moles of NH₄NO₃

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