C). if 0.5 mole of oxygen reacted with hydrogen (h2), how many mole of water (h20) was produced
from the reaction?

1 mol of water is produced in those conditions.

Explanation:

The reaction to produce water between H₂ and O₂ is this:

2H₂  +  O₂  →  2H₂O

We don't have the amount of hydrogen, so we have to think that is in excess.

Let's work with oxygen.

Ratio is 1:2

For 0.5 mole of oxygen, I will make the double of moles of water.

1.0 mol of water will be produced.

Explanation:

Step 1: Data given

Number of moles of oxygen (O2) = 0.5 moles

Step 2: The balanced equation

2H2 + O2 → 2H20

Step 3: Calculate moles of water (H20)

For 2 moles of H2 consumed, we need 1 mol of O2 to produce 2 moles of water (H2O)

For 0.5 moles of oxygen (O2) we'll have 2*0.5 = 1.0 moles of water (H20) produced

1.0 mol of water will be produced.

radioactive decay occurs in unstable atomic nuclei – that is, ones that don't have enough binding energy to hold

the nucleus together due to an excess of either protons or neutrons.

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.