I'm not good at chem. : (
c3h8 + 5o2 --> 4h2o + 3co2

if 0.45 grams of water is formed during the combustion of propane, how many grams of carbon dioxide is formed?

There will be 0.825 grams of CO2 produced

Explanation:

Step 1: Data given

Mass of water formed = 0.45 grams

Molar mass of water = 18.02 g/mol

Molar mass of CO2 = 44.01 g/mol

Step 2: The balanced equation

C3H8 + 5O2 → 4H2O + 3CO2

Step 3: Calculate moles of water

Number of moles water = mass of water / molar mass water

Number of moles water = 0.45 grams / 18.02 g/mol

Number of moles water = 0.025 moles

Step 4: Calculate moles of CO2

For 1 mol of propane we need 5 moles of O2 to produce 4 moles of H2O and 3 moles of CO2

When 0.025 moles of H2O are produced, we'll get 3/4 * 0.025 = 0.01875 moles of CO2 produced

Step 5: Calculate mass of CO2 produced

Mass of CO2 = moles of CO2 * molar mass of CO2

Mass of CO2 = 0.01875 moles * 44.01 g/mol

Mass of CO2 = 0.825 grams

There will be 0.825 grams of CO2 produced

periodic trends is an atom that gets larger as the number of electronic shells increase, the radius of atoms increases as you go down a certain group in the periodic table of elements. in general, the size of an atom will decrease as you move from left to right of a certain period.