A360. mg sample of aspirin, c9h8o4, (molar mass 180. g), is dissolved in enough water to produce 200. ml of solution. what is the molarity of aspirin in a 50. ml sample of this solution?

Molarity = 0.01 M

Explanation:

Molarity is used to measure the concentration of a solution. It will be same for the whole solution or a small amount of solution if the solution is homogeneous.

So, Molarity of 200 mL of solution = Molarity of 50 mL of solution

given mass of aspirin = 360 mg = 0.36 g

molar mass of aspirin = 180 g

Volume of solution = 200 mL = 0.2 L

Therefore, Molarity = 0.01 M

50. mL of a sample prepared by dissolving 360. mg of aspirin in 200. mL of solution, has a molarity of 0.0100 M.

First, we will convert 360. mg (0.360 g) to moles of aspirin using its molar mass (180. g/mol).

2.00 × 10⁻³ moles of aspirin are dissolved in 200. mL (0.200 L) of solution. The molarity of the solution is:

The molarity is an intrinsic property, so a 50. mL sample will have the same molarity as the 200. mL solution.

50. mL of a sample prepared by dissolving 360. mg of aspirin in 200. mL of solution, has a molarity of 0.0100 M.

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