The number of atoms in 5.78 mol nh4no3. show your work.

3.481 x 10²⁴ atoms

Explanation:

Data Given:

Number of moles of NH₄NO₃ = 5.78 mol

Number of atoms of NH₄NO₃ = ?

Solution:

Formula used

                  no. of moles = no. of atoms / Avogadro's number

As we have to find no. of atoms

So, we have to rearrange the above equation

                  no. of atoms = no. of moles x Avogadro's number . . . . . (1)

Where

Avogadro's number = 6.022 x 10²³ atoms

Put values in above Equation 1

                      no. of atoms = 5.78 mol x 6.022 x 10²³ atoms/mol

                      no. of atoms = 3.481 x 10²⁴ mol

So,

no. of atoms in 5.78 mole NH₄NO₃ = 3.481 x 10²⁴ atoms

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the ratio of the conjugate base to the acid required to attain the desired ph.