Write lewis structural formulas for the following molecules:

nh3 so2
ch3oh hno2
n2 ch2o

Answer :  The Lewis-dot structure of the following molecules are shown below.

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

(1) The given molecule is,

As we know that hydrogen has '1' valence electron, nitrogen has '5' valence electrons.

Therefore, the total number of valence electrons in = 5 + 3(1)  = 8

According to Lewis-dot structure, there are 6 number of bonding electrons and 2 number of non-bonding electrons.

(2) The given molecule is,

As we know that sulfur and oxygen has '6' valence electrons.

Therefore, the total number of valence electrons in = 6 + 2(6)  = 18

According to Lewis-dot structure, there are 8 number of bonding electrons and 10 number of non-bonding electrons.

(3) The given molecule is,

As we know that carbon has '4' valence electrons, hydrogen has '1' valence electron and oxygen has '6' valence electrons.

Therefore, the total number of valence electrons in = 4 + 4(1) + 6  = 14

According to Lewis-dot structure, there are 10 number of bonding electrons and 4 number of non-bonding electrons.

(4) The given molecule is,

As we know that hydrogen has '1' valence electron, nitrogen has '5' valence electrons and oxygen has '6' valence electrons.

Therefore, the total number of valence electrons in = 1 + 5 + 2(6) = 18

According to Lewis-dot structure, there are 8 number of bonding electrons and 10 number of non-bonding electrons.

(5) The given molecule is,

As we know that nitrogen has '5' valence electrons.

Therefore, the total number of valence electrons in = 2(5) = 10

According to Lewis-dot structure, there are 6 number of bonding electrons and 4 number of non-bonding electrons.

(6) The given molecule is,

As we know that carbon has '4' valence electrons, hydrogen has '1' valence electron and oxygen has '6' valence electrons.

Therefore, the total number of valence electrons in = 4 + 2(1) + 6  = 12

According to Lewis-dot structure, there are 8 number of bonding electrons and 4 number of non-bonding electrons.

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