When 70. milliliter of 3.0-molar na2co3 is added to 30. milliliters of 1.0-molar nahco3 the result­ing concentration of na+ is 2.0 m

Answer : The resulting concentration of ion is, 4.5 M

Explanation : Given,

Concentration of = = 3.0 M = 3.0 mol/L

Volume of = = 70 mL = 0.07 L

Concentration of = = 1.0 M = 1.0 mol/L

Volume of = = 30 mL = 0.03 L

First we have to calculate the moles of and

and,

Now we have to calculate the moles of ions.

As, 1 mole of will give 2 moles of ions

So, 0.21 moles of will give moles of ions

and,

As, 1 mole of will give 1 mole of ions

So, 0.03 moles of will give 0.03 moles of ions

So,

Total number of moles of ions = 0.42 + 0.03 =0.45 mole

Total volume of both solution = 70 mL + 30 mL = 100 mL = 0.1 L

Now we have to calculate the concentration of ions.

Therefore, the resulting concentration of ion is, 4.5 M