If a balloon had an initial volume of 100ml at pressure of 3.2 atm and the pressure was decreased to 1.9 atm, what would the new volume of the balloon be assuming constant temperature

168.4 mL

Explanation:

Data Given

initial volume V1 of gas in balloon = 100 mL

initial pressure P1 of gas in balloon = 3.2 atm

final pressure P2 of gas in balloon = 1.9 atm

final volume V2 of gas in balloon = ?

Solution:

This problem will be solved by using Boyle's law equation at constant Temperature.

The formula used

                  P1V1 = P2V2

As we have to find out Volume, so rearrange the above equation

                  V2 = P1V1 / P2

Put value from the data given

V2 = 100 mL x 3.2 atm / 1.9 atm

V2 = 168.4 mL

So the final Volume of gas in baloon =  168.4 mL

answer: mercury

explanation:

  the   balanced   equation   for   reaction of   ca metal   with   o2 to   produce   cao   is as below

2 ca+ o2→ 2 cao2

  explanation

the reaction is   balanced     since the   number of atoms   in reactant side is   equal to   number of atoms   in   product side.   for   example   they   are 2   atom of   ca in   reactant   side   and   2   atoms of ca   in   the product side.

  the   process   is a   meet the   requirement   of   redox   reaction because :     calcium   is   oxidized   from   oxidation state 0   to 2+   while   oxygen   is reduced from   oxidation   state   0   to 2-