Which of the following substances would be a poor choice for making conductive solutions?

a)
c6h12o6, ch3oh, ch3ch2oh

b)
hcl, kbr, hno3

c)
naoh, koh, lioh

a)  C₆H₁₂O₆, CH₃OH, CH₃CH₂OH

Explanation:

For a solution to be conductive, it requires to have electrolytes, that is, species that dissociate into ions and carry electrical charges.

Which of the following substances would be a poor choice for making conductive solutions?

a)  C₆H₁₂O₆, CH₃OH, CH₃CH₂OH

These species are formed exclusively by covalent bonds and they are non-electrolytes, that is, they practically do not form ions in water. Therefore, a solution containing these species would be poorly conductive.

b)  HCl, KBr, HNO₃

The species are formed by ionic and covalent bonds and are electrolytes. Thus, their solutions are conductive.

c)  NaOH, KOH, LiOH

The species are formed by ionic and covalent bonds and are electrolytes. Thus, their solutions are conductive.

i believe it is c.) 1575 j.

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml