Agas sample has an original volume of 760 ml when collected at 700 mm and 40oc. if a change is made in the gas temperature which causes the volume of the gas sample to become 420 ml at 1.25 atm, what is the new temperature?

235k

Explanation:

To solve this problem, we will use the general gas equation.

In its simplest form, the general gas equation can be represented as follows:

P1V1/T1 = P2V2/T2

P1 = 700mmHg

V1 = 760ml

T1 = 40 degrees Celsius = 40 + 273.15 = 313.15K ( conversion into standard temperature unit)

P2 = 1.25 atm

We have to covert this into the same unit as the first pressure.

760mmHg = 1atm

x mmHg = 1.25 atm

x = 1.25 * 760 = 950mmHg

V2 = 420ml

T2 = ?

Now, rearranging the equation will yield:

T2 = P2V2T1/P1V1

T2 = 950 * 420 * 313.5/700 * 760

T2 = 235.125K or -38.025 degrees celcius

explanation:

metals have excess of electrons whereas non-metals have deficiency of electrons. thus, in order to gain stability metals easily donate their electrons to the non-metals.

for example, electronic configuration of sodium is and electronic configuration of phosphorous is .

when a phosphorous atom and sodium atom combine together then sodium will donate is extra one electron to the phosphorous atom. as a result there will be formation of ionic bond between sodium and phosphorous.

the reaction will be as follows.

there, are three sodium sodium atoms and each of them will donate its one extra electron to phosphorous atom. thus, the sub-shell of phosphorous gets completely filled.  

thus, we can conclude that electrons are transferred from atoms of sodium to atoms of phosphorous. this transfer makes the sodium atoms donate one electron and the phosphorous atoms to gain one electron. as a result, the sodium and phosphorus atoms strongly attract each other.

the correct answer to this question is 2