Suppose you have a 0.0423 l sample of koh of unknown concentration. if this amount of koh is used to exactly titrate 0.0350 l of hcl that has a concentration of 0.225 m, what is the molarity of the koh? hint: remember to first get your balanced equation.

0.186 M is the molarity of the KOH.

Explanation:

To calculate the concentration of acid, we use the equation given by neutralization reaction:

where,

are the n-factor, molarity and volume of acid which is

are the n-factor, molarity and volume of base which is KOH.

We are given:

Putting values in above equation, we get:

0.186 M is the molarity of the KOH.

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