How many milliliters of 0.150 m naoh are required to neutralize 85.0 ml of 0.300 m h2so4 ? the balanced neutralization reaction is: h2so4(aq)+2naoh(aq)→na2so4(aq)+2h2o (l).

Answer : The volume of required to neutralize is, 340 mL

Explanation :

To calculate the volume of base (NaOH), we use the equation given by neutralization reaction:

where,

are the n-factor, molarity and volume of acid which is

are the n-factor, molarity and volume of base which is NaOH.

We are given:

Putting values in above equation, we get:

Hence, the volume of required to neutralize is, 340 mL

answer: i dont know the answer but this might

explanation:

l

explanation:

0.07 g/cm³

1.37 g/cm³