If 18.7 ml of 0.01500 maqueous hcl is required to titrate 15.00 ml of an aqueous solution of naoh to
the equivalence point, what is the molarity of the naoh solution?

The molarity of  NaOH is 0.02 M.

Explanation:

Given data:

Volume of HCl = 18.7 mL

Molarity of HCl = 0.01500 M

Volume of NaOH = 15.00 mL

Molarity of NaOH = ?

Solution:

M₁V₁  = M₂V₂

0.01500 M × 18.7 mL  = M₂ ×  15.00 mL

M₂ = 0.3 M.mL /15.00 mL

M₂ = 0.02 M

The molarity of  NaOH is 0.02 M.

output?

explanation:

for step 7 table c on the lab "newtons law of action"   the average time it took the car to travel .25 meters   was 1.92 seconds.

the average time it took the car to travel 0.50 meters was 2.61 seconds

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