For the reaction n₂(g) + 3h₂(g) ⇌ 2nh₃(g) what is the value of kc at 500 ∘c if the equilibrium concentrations are as follows:
[h₂] = 0.50 m , [n₂] = 0.50 m , and [nh₃] = 2.1 m ?
express the equilibrium constant to two significant figures.

Kc = 70

Explanation:

This is the reaction:

N₂(g) + 3H₂(g) ⇌ 2NH₃(g)

Let's make the expression for K, with concentration at equilibrium and in molarity.

Kc = [NH₃]²  /  [H₂]³ . [N₂]

Kc = (2.1)² / (0.5)³ . 0.5

Kc = 4.41 / 0.0625 → 70

just did the assignment and the answer was #1 +2 n

for step 7 table c on the lab "newtons law of action"   the average time it took the car to travel .25 meters   was 1.92 seconds.

the average time it took the car to travel 0.50 meters was 2.61 seconds

hope this : )