If 62.8 g ca react with 92.3 g hcl according to the reaction below, how many grams of hydrogen gas will be produced, and how many grams of the excess reactant will be left over? unbalanced equation: ca + hcl → cacl2 + h2

2.55 g of hydrogen

12.17 g calcium.

to nearest hundredth.

Explanation:

The balanced equation is:

Ca + 2HCl --->   CaCl2 + H2

Using the atomic masses

40.078 g Ca react with 72.916 g of HCl to give 2.016 g HCl

The ratio of Ca to HCl in the above is 1 to 1.81935

so 62.8 g Ca reacts with 62.8 * 1.81935 = 114.245 g HCl

so there is excess of Ca in the  given weights.

Therefore the mass of Hydrogen produced

=  (2.016 / 72.916) * 92.3

= 2.552 g of hydrogen gas.

The mass of calcium required to produce 2.552 g of hydrogen is:

(2.552 /  2.016) * 40.078

= 50.73 g

So the excess of calcium is 62.8 - 50.73

= 12.17 g.

1. they vary with a higher number because boiling is way hotter than melting