Npart b, suppose the tablet was mostly dissolved when some of your solution splashed out of the beaker as co2 continued to evolve. how would this affect the perceived mass of co2? would your final calculated mass of sodium bicarbonate in the tablet be artificially high or artificially low as a result of this splashing? choose one, and explain why.

The perceived mass of CO2 would not be affected in large quantities because the splash constitutes small particles of water with sodium bicarbonate that is still reacting. The final calculated mass of sodium bicarbonate in the tablet would be artificially low.

Explanation:

Effervescence is a chemical process that involves the reaction of an acid with a carbonate or sodium bicarbonate, releasing carbon dioxide through a liquid. An example is seen in carbonated beverages, in these the gas that escapes from the liquid is carbon dioxide. The bubbles that are seen are produced by the effervescence of the dissolved gas, which by itself is not visible in its dissolved form.

when 25.0 ml of 0.700 mol/l naoh was mixed in a calorimeter with 25.0 ml of 0.700 mol/l hcl, both initially at 20.0 °c, the temperature increased to 22.1 °c. the heat capacity of the calorimeter is 279 j/°c.

the equation for the reaction is:

naoh + hcl → nacl + h₂o

moles of hcl = 0.0250 l hcl ×

0.700

mol hcl

1 l hcl = 0.0175 mol hcl

volume of solution = (25.0 + 25.0) ml = 50.0 ml

mass of solution = 50.0 ml soln ×

1.00

ml soln

= 50.0 g soln

δt=t2-t1

= (22.1 – 20.0) °c = 2.1 °c

the heats involved are

heat from neutralization + heat to warm solution + heat to warm calorimeter = 0

q1+q2+q3=0

nδh+mcδt+cδt=0

0.0175 mol ×

δh

+ 50.0 g × 4.184 j·g⁻¹°c⁻¹ × 2.1 °c + 279 j°c⁻¹ × 2.1 °c = 0

0.0175 mol ×

δh

+ 439.32 j + 585.9 j = 0

0.0175 mol ×

δh

= -1025.22 j

δh=1025.22j0.0175 mol= -58 600 j/mol = -58.6 kj/mol

wher is the rest of the question