Assuming ideal behavior, calculate the boiling point in c of solution that contains 64.5g or the non-volatile non-electrolyte quinoline( molar mass= 129g/mole) in 500 grams of benzene. for benzene the normal boling point is 80.10 c and kb = 2.53c/m

Explanation:

The given data is as follows.

     mass of solute = 64.5 g,        mass of solvent = 500 g = 0.5 kg (as 1 kg = 1000 g),  

    Temperature = ,         = 2.53 C/m

Also, we know that the relation between change in temperature, van't Hoff factor(i) and is as follows.

where,    m = molality =

                   =

                   = 1

It is known that for non-electrolyte solute i = 1.

Hence, putting the given values into the above formula as follows.

                        =

                        = 2.53 C

Therefore, calculate the boiling point of the solution as follows.

                    80.10 C + 2.53 C

                  = 82.63 C

Thus, we can conclude that the boiling point of the solution is 82.63 C.

the electronic configuration of an atom with eight electrons is 1s²2s²2p⁴. the orbital diagrams are shown in the figure.

as per the hunds rule:

1. electrons tend to avoid being in the same orbital as per as practicable.

2. electrons in different orbitals of the same energy will have their spin parallel.

this can be illustrated from the multiplicity of the orbitals of the atom. as there are four electrons in the p orbital and p orbital has 3 sub-shells. the electrons can be fed in different ways as shown in the figure but the correct orbital diagram will be as per the hunds rule.