At 700 k, the rate constant for the following reaction is 6.2x 10-4 min-1. how many minutes are requiredfor 20 percent of a sample of cyclopropane to isomerize topropane?
c3h6(> c3h6(propane)
a. 1,120 min
b. 360 min
c. 3710 min
d. 1.4 x 10-4 min
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360 minutes are required for 20 percent of a sample of cyclopropane to isomerize topropane.

Explanation:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

As the units of rate constant is , the reaction follows first order kinetics.

Expression for rate law for first order kinetics is given by:

where,

k = rate constant  =

t = time for decomposition = ?

a = let initial amount of the reactant = 100

x = amount decayed =

a - x = amount left after decay process  = 100-20= 80

Thus 360 minutes are requiredfor 20 percent of a sample of cyclopropane to isomerize topropane.

6.4 cm (max) - 25 cm (min)

since electrons are negative the answer is neagtaive