The decomposition of hi(g) is represented by the equation
2hi(g) = h2(g) + i2(g)
the following experiment was devised to determine the equilibrium constant of the reaction.
hi (g) is introduced into five identical 400-cm3 glass bulbs, and the five bulbs are maintained at 623 k. the amount of i2 produced over time is measured by opening each bulb and titrating the contents with 0.0150 m na2s2o3 (aq). the reaction of i2 with the titrant is
i2 + 2na2s2o3 = na2s4o6 + 2nai
data for the experiment are provided in this table.
bulb initial mass of hi (g) time(hours) volume of titrant(ml)
1 0.300 2 20.96
2 0.320 4 27.90
3 0.315 12 32.31
4 0.406 20 41.50
5 0.280 40 28.68
what is the value of kc for the decomposition of hi at 623 k?

Ineed someone to see if my answers are correct! if any are wrong let me know what the correct answers would be and how to get that answer! 1. how many moles of sodium chloride are in 28 grams od nacl? a. 265 mole naclb. 856 mole naclc. 479 mole of nacld. 1.2 mole nacl < my choice2. 734 grams of lithium sulfate (li2so4) are dissolved to make 2500 ml of solution what is rhe molaratiy? a. 2.67 mb. 4.56 mc. 3.89 m < my choiced. 1.78 m3. how many grams of cacl2 would be dissolved in 3.0 l of a 0.50 m solution of cacl2? a. 250 g cacl2 b. 166.5 g cacl2c. 113.65 g cacl2d. 98 g cacl2 < my choice4. suppose you had 58.44 g of nacl and you dissolved it in exactly 2.00 liters. the molarity if the solution would be 0.5 mtrue < my choicefalse 5. i would need 22g of naoh to make a 3.0 m solution using 250 ml of solvent.true < my choicefalse6. identify the solute: you have a .0195 m solution made from using 6.5 g of solute and 3 l of solvent. identify the solute by solving for molar weight.a. the solute is nacl because the molar weight is 58.43 g/mol < my choiceb. the solute is h2so4 because the molar weight is 98.06 g/molc. the solute is cacl2 because the molar weight is 111.11 g/mol

What substance has a mass of 9.5g and volume of 2.1cm^3

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