Does 1 gram of phosphorus react with 6 grams of iodine to form 4 grams of phosphorus triodine in p4(s)+6i2(s)=4pi3(s)

No

Explanation:

One mole of P₄ react with six moles of I₂ and gives 4 moles of PI₃.

When one gram phosphorus and 6 gram of  iodine react they gives 8.234 g ram of PI₃ .

Given data:

Mass of phosphorus = 1 g

Mass of iodine = 6 g

Mass of  PI₃ = ?

Solution:

Chemical equation:

P₄ + 6I₂    →  4PI₃

Number of moles of P₄:

Number of moles = Mass /molar mass

Number of mole = 1 g / 123.9 g/mol

Number of moles  = 0.01 mol

Number of moles of I₂:

Number of moles  = Mass /molar mass

Number of moles = 6 g / 253.8 g/mol

Number of moles = 0.024 mol

Now we will compare the moles of PI₃ with I₂ and P₄.

                I₂              :              PI₃

                  6              :               4

                 0.024       :             4/6×0.024 = 0.02

                  P₄            :               PI₃

                 1                :                4

                 0.01          :               4 × 0.01 = 0.04  mol

The number of moles of PI₃ produced by I₂ are less it will be limiting reactant.

Mass of PI₃ = moles × molar mass

Mass of PI₃ = 0.02 mol × 411.7 g/mol

Mass of PI₃ =  8.234 g

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