Calculate the standard free-energy change at 25 ∘c for the following reaction:
mg(s)+fe2+(aq)→mg2+(aq)+fe(s)
express your answer to three significant figures and include the appropriate units.

Explanation:

The given reaction is:

The two half reactions and their half potentials are as follows:

E° = -2.37 V

E° = -0.44 V

Half cell with more negative potential will act as anode and half cell with less negative potential will act as cathode.

Calculate cell potential as follows:

Formula for the calculation of standard free energy is as follows:

F = 96500 c/mol

n for the given reaction is 2.

the answer for sodium is 0.186

the answer for rubidium is 0.251

the awnser is group 12