Plss i'm really stuck!

how would you make a 500.0ml of stock solution of 6.0m of naoh. explain in detail with words and support with calculations.

The steps are explained below, the essential step is to find mass here, 120 g of NaOH.

Explanation:

In order to answer this question, we need to define molarity conceptually firstly to see what variables we need. According to the formula, molarity is equal to the ratio between moles and volume, while moles itself is a ratio between mass and molar mass. This means we have a formula for molarity involving mass, molar mass and volume:

In order to prepare a 500.0 mL of stock solution of 6.0 M of NaOH, we then need to find the mass of NaOH dissolved in this solution using the equation above:

Now, since we have the mass of NaOH, we can describe the steps needed to prepare this solution:

Our solution is prepared.

idk what the question is about