The reaction below has a kc value of 61. what is the value of kp for this reaction at 500 k?

n2(g) + 3 h2(g) ⇌ 2 nh3(g)

Kp = 3.62 x 10 ^ -2  

Explanation:

The relationship between Kc and Kp is given as:

Kp =  Kc (RT) ^ Δn (1)

Where:

Kp = Equilibrium Constant in terms of Molar concentrations = 61

Kc = Equilibrium Constant in terms of Partial Pressures

R = Gas Constant = 0.0821 litre.atm/mole.K

Δn = (Total No. of moles of products) - (Total No. of moles of reactants)

Δn = (2) - (3+1) = -2

T = Temperature (K) = 500 K

Substituting all values in equation (1), we get,

Kp = 61 x [ 0.0821 x 500 ] ^ (-2)

Kp = 3.62 x 10 ^ -2  

i think a, hope it .

explanation:

the answer is c i took the test