Drag the correct symbol to the equation. not all symbols will be used.

a plutonium atom undergoes nuclear fission. identify the missing element in the nuclear equation.
239pu + 1n > + 134xe + 3 1n
94 0 54 0

options:
101zr
40

134xe
54

105zr
40

103zr
40

102xe
54

Explanation:

The nuclear equation from which you have to identify the missing element is:

The superscripts to the left of each chemical symbol are the mass number of the atoms (number of protons plus neutrons) and the subscripts to the left of the chemical symbols are the atomic numbers of the atoms (number of protons).

Thus, such equation must be read as "an atom of plutonium-239 is bombarded with a neutron and produces one atom of an unkwon element, one atom of xenon-134, and 3 neutrons".

To find the identity of the missing element you must do two balances: mass number and atomic number.

Mass number:

Hence, the mass number of the missing element is 103.

Atomic number:

Hence, the atomic number of the missing element is 40.

In a periodic table you can find that the element with atomic number 40 is zirconium, Zr.

Thus, the identity of the missing isotope is zirconium-103, ¹⁰³₄₀Zr.

And the complete equation is:

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

answer: they produce more slow than unicellular organisms.