Apoint charge q₁ = +3.00 µc is held stationary at the origin. a second point charge q₂ = -4.30 µc moves from the point x = 0.110 m, y = 0 to the point x = 0.250 m, y = 0.250 m. how much work is done by the electric force on q₂?

the work done by the electric force on the second charge is W= 0.72 J

Explanation:

the initial distance d₁ between the charges is

d₀=√(x₀² + y₀²)= √[(0.110m)² + 0²] = 0.110 m

the final distance d between the charges is

d=√(x² + y²)= √[(0.250m)² + (0.250m)²] = 0.353m

the work done by the electric force on the second charge  is

W= k*q₂*q₁*(1/d-1/d₀)

where

W= work that was done by the electric force on the second charge

k = coulomb's constant = 8.987*10⁹ N·m²/C²

q₂ and q₁ = electric charge of the second and first charge respectively

replacing values

W= k*q₂*q₁*(1/d-1/d₀) = 8.987*10⁹ N·m²/C²*(-4.30*10⁻⁶ C)*(3.00*10⁻⁶C)*( 1/0.353m - 1/0.110 m) = 0.72 N*m = 0.72 J

W= 0.72 J

in chemistry, adhesion and cohesion are attractive forces that exist between molecules. they hold the molecules together from each other. they are different in that adhesive force exists between molecules of different substance while cohesive force happens between molecules of same substance.

adhesion between water and glass causes water molecules at the edge of water and glass interface to climb up the wall in a narrow glass tube. this is called capillary action. cohesion is what gives glass its shape and causes water to form a droplet.

2b2t

explanation:

2b2t