a chemical reaction produces oxygen gas. you collect 3.00×1023 oxygen gas molecules at stp .

what volume of oxygen gas did you collect?

We will collect 11.17 liters of oxygen gas.

Explanation:

Where:

N = Number of particles / atoms/ molecules

n = Number of moles

= Avogadro's number

We have:

Molecules of oxygen gas N =

n =?

n = 0.4982 moles of oxygen

Using ideal gas equation:

PV = nRT

where,

P = Pressure of gas = 1 atm (at STP)

V = Volume of gas = 10 L

n = number of moles of gas = ?

R = Gas constant = 0.0821 L.atm/mol.K

T = Temperature of gas = 273.15 K  (at STP)

Putting values in above equation, we get:

V = 11.17 L

We will collect 11.17 liters of oxygen gas.