Zinc will react with hydrochloric acid to produce hydrogen gas. zn(s)+2hcl(aq)⟶zncl2(aq)+h2(g)what is the volume of h2 gas produced if 2.00g of zinc is used with an excess of hydrochloric acid in the reaction above at stp? round to 3 significant figures.

0.690 liters is the volume of hydrogen gas produced if 2.00 grams of zinc is used with an excess of hydrochloric acid.

Explanation:

Mole so zinc =

According to reaction, 1 mole of zinc gives 1 mole of hydrogen gas.

Then 0.03077  mole of zinc will give :

of hydrogen gas

Pressure of hydrogen gas ,P= 1 atm

Temperature  of of hydrogen gas ,T= 273.15 K

Volume of hydrogen gas = V = ?

Moles of hydrogen gas = 0.03077 mol

PV = nRT (Ideal gas equation )

V = 0.690 L

0.690 liters is the volume of hydrogen gas produced if 2.00 grams of zinc is used with an excess of hydrochloric acid.

the ratio of the conjugate base to the acid required to attain the desired ph.