For each atom in its ground state, determine the number of electrons in each energy shell. if there are no electrons in an energy shell, enter a 0 for that shell. na , na, energy shell 1: na , na, energy shell 2: na , na, energy shell 3: na , na, energy shell 4: al , al, energy shell 1: al , al, energy shell 2: al , al, energy shell 3: al , al, energy shell 4: p , p, energy shell 1: p , p, energy shell 2: p , p, energy shell 3: p , p, energy shell 4: s , s, energy shell 1:

thats a little if u want the answer just look it up on google thats what i do haha : )

with this one i know the answer in craters one reason i looked it up and i learned about it there is my evidence

metric time was an attempt to create a standard unit of time based off of 10, but it never took off an is not included in the metric system (si)

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole