For the reaction 6co2(g) + 6h2o(l) > c6h12o6(s) + 6o2(g), what mass, in grams, of glucose is produced from 3.00 moles of carbon dioxide?

Mass = 90.1 g

Explanation:

Given data:

Number of moles of carbon dioxide = 3 moles

Mass of glucose produced = ?

Solution:

Chemical equation:

6H₂O + 6CO₂   →   C₆H₁₂O₆ + 6O₂

Now we will compare the moles of CO₂ and C₆H₁₂O₆.

                     CO₂      :      C₆H₁₂O₆

                        6        :           1

                         3       :          0.5

Mass of glucose:

Mass = number of moles × molar mass

Mass = 0.5 mol × 180.2 g/mol

Mass = 90.1 g

it is a good conductor

explanation: