Quicklime, cao, can be prepared by roasting limestone, caco3, according to the following reaction. caco3(s) ∆→ cao(s) + co2(g). when 2.00 × 103 g caco3 is heated, the actual yield of cao is 1.05 × 103 g. what is the percentage yield?

93.71 %

Explanation:

The formula for the calculation of moles is shown below:

For  :-

Mass of  = g

Molar mass of water = 100.0869 g/mol

The formula for the calculation of moles is shown below:

Thus,

According to the given reaction:

1 mole of on reaction forms 1 mole of

19.98 mole of on reaction forms 19.98 mole of

Moles of = 19.98 moles

Molar mass of = 56.0774 g/mol

Mass of sodium sulfate = Moles × Molar mass = 19.98 × 56.0774 g = 1120.43 g

The expression for the calculation of the percentage yield for a chemical reaction is shown below as:-

Given , Values from the question:-

Theoretical yield = 1120.43 g

Experimental yield = 1050 g

Applying the values in the above expression as:-

98.16% is the correct answer.

Explanation:

is it a purebred? it looks more like a red nose, but it doesn't have the red could it be a staffordshire bull terrior? unsure if that's the right name for it sorry

"standard molar enthalpy:

h2o ( liquid water ) : - 285.8 kj/mole

h2o ( water vapor ) : - 241.8 kj / mole.

δhrxn = - 241. 8 - ( - 285.8 )= -241.8 + 285.8 = 44.0

answer: 44.0 kj"