Consider the following reaction at equilibrium. what effect will increasing the temperature have on the system? fe3o4(s) + co(g) ↔ 3 feo(s) + co2(g) δh°= +35.9 kjthe equilibrium constant will decrease. no effect will be observed. the reaction will shift to the right in the direction of products. the equilibrium constant will increase. the reaction will shift to the left in the direction of reactants

The reaction will shift to the right in the direction of products.

Explanation:

According to Le Chatelier's Principle, the change in any state of the equilibrium say temperature, volume, pressure, or the concentration, the equilibrium will oppose these changes and will shift in such a way that the effect cause must be nullified.

For an endothermic reaction,

On increasing the temperature, reaction will go in forward direction (towards right), because according to Le Chatelier's principle as we increase the temperature,  the equilibrium is will be disturbed , so to again establish the equilibrium, the reaction will go in forward direction as it is endothermic in nature (towards right).

Thus, the of the given reaction is positive and thus, on increasing temperature, reaction will go in forward direction.

- The reaction will shift to the right in the direction of products.

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.