The temperature of 200 ml of gas
originally at stp is changed to -25 celsius at constant volume. calculate the final pressure of the gas in torr

691.6 torr

Explanation:

Given data:

Initial temperature = 273 K

Initial pressure = 1 atm

Final temperature = -25 °C (-25 + 273 = 248 k)

Final pressure = ?

Solution:

P₁/T₁ = P₂/T₂

P₁ = Initial pressure

T₁ = Initial temperature

P₂ = Final pressure  

T₂ = Final temperature

Now we will put the values in formula.

P₁/T₁ = P₂/T₂

P₂ = P₁T₂/T₁  

P₂ = 1 atm × 248 K / 273 k

P₂ =248  atm. K / 273 K

P₂ = 0.91 atm  

In torr:

0.91  × 760 = 691.6 torr

the reaction mixture contains some ammonia, plus a lot of unreacted nitrogen and hydrogen. the mixture is cooled and compressed, causing the ammonia gas to condense into a liquid. the liquefied ammonia is separated and removed. the unreacted nitrogen and hydrogen are then recycled back into the reactor .

16

explanation:

the marks go by 4s