Use the equation below to determine how many liters of nh3 are needed to react completely with 10.0 l of no (at stp)? your answer should be in the following format: 1.22 l
4nh3+6no=5no+6h2o

We need 6.65 L of NH3 to react with 10.0 L of NO

Explanation:

Step 1: Data given

volume of NO = 10.0 L

at STP 1 mol has a volume of 22.4 L

Step 2: The balanced equation

4NH3+6NO → 5N2+6H2O

Step 3: Calculate moles of NO

Since 22.4 L = 1 mol

10.0 L = 0.446 mol

Step 4: Calculate moles of NH3

For 6 moles NO, we need 4 moles of NH3 to produce 5 moles of N2 and 6 moles of H2O

for 0.446 moles of NO, we have  4/6 * 0.446 = 0.297 moles of NH3

Step 5: Calculate volume of NH3

1 mol = 22.4 L

0.297 mol = 22.4 * 0.297 = 6.65 L

We need 6.65 L of NH3 to react with 10.0 L of NO

6.67 L

Explanation:

The correct equation is:

 ⇒  

4 moles of reacts completely with 6 moles of NO to give 5 moles of .

At standard temperature and pressure volume is directly proportional to number of moles of gas.

Hence we can say that :

4L of reacts with 6L of NO.

Then to get 10L of NO L of should react.

=L

answercontent filtering;

the term hydride is commonly named after binary compounds that hydrogen forms with other elements of the periodic table. hydride compounds in general form with almost any element, except a few noble gases. the trends and properties vary according to the type of intermolecular force that bonds the elements together, the temperature, its molecular masses, and other components. hydrides are classified into three major groups, depending on what elements the hydrogen bonds to. the three major groups are covalent, ionic, and metallic hydrides. formally, hydride is known as the negative ion of a hydrogen, h-, also called a hydride ion. because of this negative charge, hydrides have reducing, or basic properties. its special characteristics will be further discussed.

explanation: