Azomethane decomposes into nitrogen and ethane at elevated temperature: h3c–n=n–ch3 → n2 + c2h6a chemist studying this reaction at 300°c begins an experiment with an azomethane concentration of 4.11 mm and obtains the following data: col1 time(s) 100 150 200 250 300col2 [azomethane] (mm) 3.18 2.80 2.47 2.17 1.91calculate the rate constant. give an answer with concentration units of molarity and time units of seconds.

k = 0,0025 s⁻¹

Explanation:

To calculate the rate constant it is necessary to find out the order of reaction.

For zeroth order the integrated rate law is:

[A] = [A]₀ -kt

The graph of [A] vs t gives a correlation coefficient R² of 0,9948.

The first order is:

ln [A] = ln [A]₀ -kt

The graph of ln [A] vs t gives a R² of 1

The second order is:

1/[A] = 1/[A]₀ -kt

The graph of 1/[A] vs t gives a R² of 0,9939

As R² = 1 for first order, the descomposition of azomethane follows this kinetics order. The lineal correlation is:

y = b - mx

y = 1,412 - 0,0025x

ln [A] = ln [A]₀ -kt

That means:

-k = - 0,0025 s⁻¹

k = 0,0025 s⁻¹

I hope it helps!

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer

c-14 is carbon-14, or radiocarbon.   it is a radioactive isotope of carbon with an atomic nucleus containing 6 protons and 8 neutrons.