Calculate the energy in joules to heat 828 g of
mercury from 37.0◦ c to 42.0◦ c. the specific
heat capacity of hg(ℓ) is 0.139 j/g·
◦c.
answer in units of joules.

There is 575.46 J of heat released

Explanation:

Step 1: Data given

Mass of mercury = 828 grams

Heat capacity of mercury = 0.139J/g°C

Initial temperature = 37.0°C

Final temperature = 42.0 °C

Step 2: Calculate heat released

Q = m*c*ΔT

⇒ Q =the heat released in Joule

⇒ m = the mass of mercury = 828 grams

⇒ c = the heat capacity of mercury = 0.139 J/g°C

 ⇒ ΔT = the change of temperature = T2 - T1 = 42.0 - 37.0 = 5.0 °C

Q = 828 g * 0.139 J/g°C * 5.0 °C

Q = 575.46 J

There is 575.46 J of heat released

yes they ca   is ur ansswerrr

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.