How many grams of sodium oxide can be produced when 55.3 g na react with 64.3 g o2?

unbalanced equation: na + o2 → na2o

show, or explain, all of your work along with the final answer.

Given the two amounts of reactants, we get the limiting reactant between the two. We convert each to mole and divide them to their corresponding stoichiometric coefficient. we balance first above, that is 4Na+O2=2Na2O. hence, for Na that is 0.60 mole and oxygen is 2.00 mole. We follow the smaller amount, Na, hence the amount of sodium oxide in grams is 74.53 grams. 

Sorry i dont understand the question can you rephase it?