How many moles of cao form when 98.60 g caco3 decompose

We are given the amount of CaCO3 to decompose when heated. This will be our starting point.

98.60 g CaCO3 ( 1 mol CaCO3 / 100.09 grams CaCO3) (1 mol CaO / 1 mol CaCO3 ) ( 56.08 g O2 / 1 mol CaO) =  55.25 g CaO

answer; 4 electrons;