Chemistry, 12.12.2019 18:31 tylerharmsss

An oxidation-reduction reaction that is also a synthesis reaction

a. 2mg(s) + o2(g) --> 2 mgo(s)
b. pb^2+(aq) + cro4^2-(> pbcro4(s)

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Answer from: jules8022

$\rm 2\;Mg\;(s)\;+\;O_2\;(g)\;\rightarrow\;2\;MgO\;(s)$ , this is the redox reaction and also a synthesis reaction.

A redox reaction is that where reduction and oxidation take simultaneously.

The synthesis reaction is one in which the product is formed.

(A) The reaction of Mg with $\rm O_2$ will form MgO.

Since there is the formation of the product by reaction of 2 reagents, it is a synthesis reaction.

In this reaction, Mg is getting oxidized and oxygen is getting reduced.

So this is a redox reaction as well.

(B) The reaction of Pb with chromate will result in $\rm PbCrO_4$ .

There is a formation of product in the reaction, so it is a synthesis reaction.

There is no change in the oxidation state of lead, so it is not a redox reaction.

For more information about oxidation-reduction reaction, refer the link:

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Answer from: onlymyworld27

The oxidation reduction reaction which is also a synthesis reaction is:

A. $2Mg(s)+O_{2}(g)\rightarrow 2MgO(s)$ .

Explanation:

A Synthesis reaction is a reaction in which two or more reactants combine to form a single product.

A redox reaction(oxidation reduction) is a reaction in which one species is oxidised and one is reduced simultaneously.

Oxidation: Loss of electron or increase in oxidation state

Reduction: Gain of electron or decrease in oxidation state

In both cases A,B two reactant are combining to give a single compound.So both are synthesis reaction.

A. $2Mg(s)+O_{2}(g)\rightarrow 2MgO(s)$ is a redox reaction :

Oxidation of Mg : $2Mg(s)\rightarrow 2Mg^{2+}+4e^{-}$

(increase in oxidation state of Mg from 0 to +2)

Reduction of Oxygen: $O_{2}(g)+4e^{-}\rightarrow 2O^{2-}$

(decrease in oxidation state of O from 0 to -2)

on combining above half-reactions:

$2Mg(s)+O_{2}(g)\rightarrow 2MgO(s)$

Its both redox and synthesis reaction.

But there is no change in oxidation states of elements in Reaction B

$Pb^{2+}(aq)+CrO_{4}^{2-}\rightarrow PbCrO_{4}(s)$

oxidation state of Pb is (+2) in both $Pb^{2+}$ and $PbCrO_{4}$ :

$Pb^{2+}\rightarrow PbCrO_{4}$

Cr has (+6) oxidation state in both $CrO_{4}{2-}$ and $PbCrO_{4}$ :

$CrO_{4}{2-}\rightarrow PbCrO_{4}$

No change in oxidation state so no loss/gain of electrons .Hence not a redox reaction

B. is not a oxidation reduction reaction ,its just a synthesis reaction.

Hence,

The oxidation reduction reaction which is also a synthesis reaction is:

A. $2Mg(s)+O_{2}(g)\rightarrow 2MgO(s)$ .

Answer from: Quest

Ch4 is nonpolar and insoluble in water. since all of the hydrogen atoms are evenly spread around the carbon atom even through the c h bond is polar all the poles cancel each other out.

Answer from: Quest

i think slash and

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An oxidation-reduction reaction that is also a synthesis reaction

a. 2mg(s) + o2(g) --&g...

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