Question 6
a 9.0-kg crate rests on a frictionless surface. it then experiences a net horizontal force of 45. newtons. what is the resulting acceleration of the crate?
a
0.0 m/s2

b
0.20 m/s2

c
5.0 m/s2

d
36 m/s2

C 5.0 m/s²

Explanation:

Given data

Mass (m): 9.0 kg

Force (F): 45 N

A 9.0-kg crate rests on a frictionless surface, thus, the only horizontal force to consider is that of 45 N. We can find the acceleration of the 9.0-kg crate due to the 45 N force using Newton's second law of motion.

F = m × a

a = F/m = 45 N/9.0 kg = 5.0 m/s²

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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