In the reaction of zn with hci, 140.15 g of zncl2 was actually formed, although the theoretical yield
was 143 g. what was the percent yield?

Percent yield of ZnCl₂ = 98 %

Explanation:

Data Given:

Actual yield of ZnCl₂ = 140.15 g

Theoretical yield of ZnCl₂ =  143 g.

percent yield = ?

Solution:

Formula used

          Percent yield = Actual yield / Theoretical yield x 100%

Put values in the formula

           Percent yield = 140.15 g / 143 g x 100%

           Percent yield = 98.007 %

Rounded to significant figure

Percent yield of ZnCl₂ = 98 %

pure substance: iron,copper

impure substance: water,charcoal